What is the integral of e^{-1/4 x} ?

The integral of e^{-1/4 x} is -4e^{-x/4}+C

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integral of e^{-1/4 x}

\int e^{- \frac{1}{4} x} d x

- 4 e^{- \frac{x}{4}} + C

Solution steps

\int e^{- \frac{1}{4} x} d x

Simplify

- \frac{1}{4} x : - \frac{x}{4}

= \int e^{- \frac{x}{4}} d x

Apply u-substitution

: \int - 4 e^{u} d u

= \int - 4 e^{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 4 \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= - 4 e^{u}

Substitute back

u = - \frac{x}{4}

= - 4 e^{- \frac{x}{4}}

Add a constant to the solution

= - 4 e^{- \frac{x}{4}} + C

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