What is the integral of (-9sec(x)tan(x)-7sec^2(x)) ?

The integral of (-9sec(x)tan(x)-7sec^2(x)) is -9sec(x)-7tan(x)+C

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integral of (-9sec(x)tan(x)-7sec^2(x))

\int (- 9 sec (x) tan (x) - 7 sec^{2} (x)) d x

- 9 sec (x) - 7 tan (x) + C

Solution steps

\int - 9 sec (x) tan (x) - 7 sec^{2} (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 9 sec (x) tan (x) d x - \int 7 sec^{2} (x) d x

\int 9 sec (x) tan (x) d x = 9 sec (x)

\int 7 sec^{2} (x) d x = 7 tan (x)

= - 9 sec (x) - 7 tan (x)

Add a constant to the solution

= - 9 sec (x) - 7 tan (x) + C

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\int x^{2} - 10 x + 25 d x

What is the integral of (-9sec(x)tan(x)-7sec^2(x)) ?
The integral of (-9sec(x)tan(x)-7sec^2(x)) is -9sec(x)-7tan(x)+C