What is the integral of (x^{-1})/2 ?

The integral of (x^{-1})/2 is 1/2 ln|x|+C

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integral of (x^{-1})/2

integral

\frac{x ^{- 1}}{2}

\frac{1}{2} ln ∣ x ∣ + C

Solution steps

\int \frac{x ^{- 1}}{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int x^{- 1} d x

Use the common integral:

\int x^{- 1} d x = ln (∣ x ∣)

= \frac{1}{2} ln ∣ x ∣

Add a constant to the solution

= \frac{1}{2} ln ∣ x ∣ + C

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