What is the integral of 4xsec^2(x^2) ?

The integral of 4xsec^2(x^2) is 2tan(x^2)+C

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integral of 4xsec^2(x^2)

\int 4 x sec^{2} (x^{2}) d x

2 tan (x^{2}) + C

Solution steps

\int 4 x sec^{2} (x^{2}) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int x sec^{2} (x^{2}) d x

Apply u-substitution

: \int \frac{sec ^{2} ( u )}{2} d u

= 4 \cdot \int \frac{sec ^{2} ( u )}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \frac{1}{2} \cdot \int sec^{2} (u) d u

Use the common integral:

\int sec^{2} (u) d u = tan (u)

= 4 \cdot \frac{1}{2} tan (u)

Substitute back

u = x^{2}

= 4 \cdot \frac{1}{2} tan (x^{2})

Simplify

4 \cdot \frac{1}{2} tan (x^{2}) : 2 tan (x^{2})

= 2 tan (x^{2})

Add a constant to the solution

= 2 tan (x^{2}) + C

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What is the integral of 4xsec^2(x^2) ?
The integral of 4xsec^2(x^2) is 2tan(x^2)+C