What is the integral of (x^4+x^2+1)/(x^2) ?

The integral of (x^4+x^2+1)/(x^2) is (x^3)/3+x-1/x+C

Popular >

integral of (x^4+x^2+1)/(x^2)

\int \frac{x ^{4} + x ^{2} + 1}{x ^{2}} d x

\frac{x ^{3}}{3} + x - \frac{1}{x} + C

Solution steps

\int \frac{x ^{4} + x ^{2} + 1}{x ^{2}} d x

Expand

\frac{x ^{4} + x ^{2} + 1}{x ^{2}} : x^{2} + 1 + \frac{1}{x ^{2}}

= \int x^{2} + 1 + \frac{1}{x ^{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{2} d x + \int 1 d x + \int \frac{1}{x ^{2}} d x

\int x^{2} d x = \frac{x ^{3}}{3}

\int 1 d x = x

\int \frac{1}{x ^{2}} d x = - \frac{1}{x}

= \frac{x ^{3}}{3} + x - \frac{1}{x}

Add a constant to the solution

= \frac{x ^{3}}{3} + x - \frac{1}{x} + C

\int sec (x) (4 tan (x) + 5 sec (x)) d x

\int \frac{1}{r + 1} d r

\int e^{2 x} cos (π) x d x

\int \frac{50}{x + 5} d x

\int \frac{1}{( x + 5 )} d x

What is the integral of (x^4+x^2+1)/(x^2) ?
The integral of (x^4+x^2+1)/(x^2) is (x^3)/3+x-1/x+C