What is the integral of 1/9 cos(x) ?

The integral of 1/9 cos(x) is 1/9 sin(x)+C

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integral of 1/9 cos(x)

\int \frac{1}{9} cos (x) d x

\frac{1}{9} sin (x) + C

Solution steps

\int \frac{1}{9} cos (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{9} \cdot \int cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= \frac{1}{9} sin (x)

Add a constant to the solution

= \frac{1}{9} sin (x) + C

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