What is the integral of cot(41x) ?

The integral of cot(41x) is 1/41 ln|sin(41x)|+C

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integral of cot(41x)

\int cot (41 x) d x

\frac{1}{41} ln ∣ sin (41 x) ∣ + C

Solution steps

\int cot (41 x) d x

Rewrite using trig identities

= \int \frac{cos ( 41 x )}{sin ( 41 x )} d x

Apply u-substitution

: \int \frac{1}{41 u} d u

= \int \frac{1}{41 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{41} \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= \frac{1}{41} ln ∣ u ∣

Substitute back

u = sin (41 x)

= \frac{1}{41} ln ∣ sin (41 x) ∣

Add a constant to the solution

= \frac{1}{41} ln ∣ sin (41 x) ∣ + C

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What is the integral of cot(41x) ?
The integral of cot(41x) is 1/41 ln|sin(41x)|+C