What is the integral of (12x+5)sqrt(6x^2+5x) ?

The integral of (12x+5)sqrt(6x^2+5x) is 2/3 (6x^2+5x)^{3/2}+C

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integral of (12x+5)sqrt(6x^2+5x)

\int (12 x + 5) 6 x^{2} + 5 x d x

\frac{2}{3} (6 x^{2} + 5 x)^{\frac{3}{2}} + C

Solution steps

\int (12 x + 5) 6 x^{2} + 5 x d x

Apply u-substitution

: \int u d u

= \int u d u

Apply the Power Rule

: \frac{2}{3} u^{\frac{3}{2}}

= \frac{2}{3} u^{\frac{3}{2}}

Substitute back

u = 6 x^{2} + 5 x

= \frac{2}{3} (6 x^{2} + 5 x)^{\frac{3}{2}}

Add a constant to the solution

= \frac{2}{3} (6 x^{2} + 5 x)^{\frac{3}{2}} + C

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What is the integral of (12x+5)sqrt(6x^2+5x) ?
The integral of (12x+5)sqrt(6x^2+5x) is 2/3 (6x^2+5x)^{3/2}+C