What is the integral of 2x^2+4x-6 ?

The integral of 2x^2+4x-6 is (2x^3)/3+2x^2-6x+C

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integral of 2x^2+4x-6

\int 2 x^{2} + 4 x - 6 d x

\frac{2 x ^{3}}{3} + 2 x^{2} - 6 x + C

Solution steps

\int 2 x^{2} + 4 x - 6 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 x^{2} d x + \int 4 x d x - \int 6 d x

\int 2 x^{2} d x = \frac{2 x ^{3}}{3}

\int 4 x d x = 2 x^{2}

\int 6 d x = 6 x

= \frac{2 x ^{3}}{3} + 2 x^{2} - 6 x

Add a constant to the solution

= \frac{2 x ^{3}}{3} + 2 x^{2} - 6 x + C

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What is the integral of 2x^2+4x-6 ?
The integral of 2x^2+4x-6 is (2x^3)/3+2x^2-6x+C