What is the integral of (2x+6)/(x^2+4x+5) ?

The integral of (2x+6)/(x^2+4x+5) is ln|x^2+4x+5|+2arctan(x+2)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (2x+6)/(x^2+4x+5)

\int \frac{2 x + 6}{x ^{2} + 4 x + 5} d x

ln x^{2} + 4 x + 5 + 2 arctan (x + 2) + C

Solution steps

\int \frac{2 x + 6}{x ^{2} + 4 x + 5} d x

Complete the square

x^{2} + 4 x + 5 : (x + 2)^{2} + 1

= \int \frac{2 x + 6}{( x + 2 ) ^{2} + 1} d x

Apply u-substitution

: \int \frac{2 u + 2}{u ^{2} + 1} d u

= \int \frac{2 u + 2}{u ^{2} + 1} d u

Expand

\frac{2 u + 2}{u ^{2} + 1} : \frac{2 u}{u ^{2} + 1} + \frac{2}{u ^{2} + 1}

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{2 u}{u ^{2} + 1} d u + \int \frac{2}{u ^{2} + 1} d u

\int \frac{2 u}{u ^{2} + 1} d u = ln u^{2} + 1

\int \frac{2}{u ^{2} + 1} d u = 2 arctan (u)

= ln u^{2} + 1 + 2 arctan (u)

Substitute back

u = x + 2

= ln (x + 2)^{2} + 1 + 2 arctan (x + 2)

Expand

(x + 2)^{2} + 1 : x^{2} + 4 x + 5

= ln x^{2} + 4 x + 5 + 2 arctan (x + 2)

Add a constant to the solution

= ln x^{2} + 4 x + 5 + 2 arctan (x + 2) + C

\int 6 e^{6 s} sin (e^{6 s}) d s

\int 2 x y + 3 d x

\int \frac{x ^{2}}{( 5 x + 7 ) ^{3}} d x

\int 3 x (x^{2} + 1)^{\frac{3}{2}} d x

\int x e^{z} d z

What is the integral of (2x+6)/(x^2+4x+5) ?
The integral of (2x+6)/(x^2+4x+5) is ln|x^2+4x+5|+2arctan(x+2)+C