What is the integral of sin((4t)/3) ?

The integral of sin((4t)/3) is -3/4 cos((4t)/3)+C

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integral of sin((4t)/3)

\int sin (\frac{4 t}{3}) d t

- \frac{3}{4} cos (\frac{4 t}{3}) + C

Solution steps

\int sin (\frac{4 t}{3}) d t

Apply u-substitution

: \int sin (u) \frac{3}{4} d u

= \int sin (u) \frac{3}{4} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{3}{4} \cdot \int sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= \frac{3}{4} (- cos (u))

Substitute back

u = \frac{4 t}{3}

= \frac{3}{4} (- cos (\frac{4 t}{3}))

Simplify

= - \frac{3}{4} cos (\frac{4 t}{3})

Add a constant to the solution

= - \frac{3}{4} cos (\frac{4 t}{3}) + C

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What is the integral of sin((4t)/3) ?
The integral of sin((4t)/3) is -3/4 cos((4t)/3)+C