What is the integral of 6xcos(2x) ?

The integral of 6xcos(2x) is 3xsin(2x)+3/2 cos(2x)+C

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integral of 6xcos(2x)

\int 6 x cos (2 x) d x

3 x sin (2 x) + \frac{3}{2} cos (2 x) + C

Solution steps

\int 6 x cos (2 x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int x cos (2 x) d x

Apply u-substitution

: \int \frac{u cos ( u )}{4} d u

= 6 \cdot \int \frac{u cos ( u )}{4} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \frac{1}{4} \cdot \int u cos (u) d u

Apply Integration By Parts

: u sin (u) - \int sin (u) d u

= 6 \cdot \frac{1}{4} (u sin (u) - \int sin (u) d u)

\int sin (u) d u = - cos (u)

= 6 \cdot \frac{1}{4} (u sin (u) - (- cos (u)))

Substitute back

u = 2 x

= 6 \cdot \frac{1}{4} (2 x sin (2 x) - (- cos (2 x)))

Simplify

6 \cdot \frac{1}{4} (2 x sin (2 x) - (- cos (2 x))) : 3 x sin (2 x) + \frac{3}{2} cos (2 x)

= 3 x sin (2 x) + \frac{3}{2} cos (2 x)

Add a constant to the solution

= 3 x sin (2 x) + \frac{3}{2} cos (2 x) + C

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What is the integral of 6xcos(2x) ?
The integral of 6xcos(2x) is 3xsin(2x)+3/2 cos(2x)+C