What is the integral of (1/(xsqrt(9x^2-1))) ?

The integral of (1/(xsqrt(9x^2-1))) is arctan(sqrt(9x^2-1))+C

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integral of (1/(xsqrt(9x^2-1)))

\int (\frac{1}{x 9 x ^{2} - 1}) d x

arctan (9 x^{2} - 1) + C

Solution steps

\int \frac{1}{x 9 x ^{2} - 1} d x

Apply u-substitution

: \int \frac{1}{u ^{2} + 1} d u

= \int \frac{1}{u ^{2} + 1} d u

Use the common integral:

\int \frac{1}{u ^{2} + 1} d u = arctan (u)

= arctan (u)

Substitute back

u = 9 x^{2} - 1

= arctan (9 x^{2} - 1)

Add a constant to the solution

= arctan (9 x^{2} - 1) + C

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What is the integral of (1/(xsqrt(9x^2-1))) ?
The integral of (1/(xsqrt(9x^2-1))) is arctan(sqrt(9x^2-1))+C