What is the integral of x+4/(sqrt(x)) ?

The integral of x+4/(sqrt(x)) is (x^2)/2+8sqrt(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of x+4/(sqrt(x))

\int x + \frac{4}{x} d x

\frac{x ^{2}}{2} + 8 x + C

Solution steps

\int x + \frac{4}{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x d x + \int \frac{4}{x} d x

\int x d x = \frac{x ^{2}}{2}

\int \frac{4}{x} d x = 8 x

= \frac{x ^{2}}{2} + 8 x

Add a constant to the solution

= \frac{x ^{2}}{2} + 8 x + C

\int x^{2} cos (4 x^{3}) d x

\int - 6 arccos (3 x) d x

\int \frac{1}{e ^{3 t}} d t

\int 2 θ d θ

\int \frac{1}{- u + 1} d u

What is the integral of x+4/(sqrt(x)) ?
The integral of x+4/(sqrt(x)) is (x^2)/2+8sqrt(x)+C