What is the integral of 3x^2+sqrt(x) ?

The integral of 3x^2+sqrt(x) is x^3+2/3 x^{3/2}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 3x^2+sqrt(x)

\int 3 x^{2} + x d x

x^{3} + \frac{2}{3} x^{\frac{3}{2}} + C

Solution steps

\int 3 x^{2} + x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 x^{2} d x + \int x d x

\int 3 x^{2} d x = x^{3}

\int x d x = \frac{2}{3} x^{\frac{3}{2}}

= x^{3} + \frac{2}{3} x^{\frac{3}{2}}

Add a constant to the solution

= x^{3} + \frac{2}{3} x^{\frac{3}{2}} + C

3 sin (x)

\int 6 e^{x} - x d x

\int \frac{10 x}{x ^{2} + 7 x + 6} d x

\int (\frac{1}{x ( ln ( x ) ) ^{2}}) d x

\int \frac{6 x ^{2} + 10 x + 2}{x ^{3} + 3 x ^{2} + 2 x} d x

What is the integral of 3x^2+sqrt(x) ?
The integral of 3x^2+sqrt(x) is x^3+2/3 x^{3/2}+C