What is the integral of (1+tan(x))/2 ?

The integral of (1+tan(x))/2 is 1/2 (x-ln|cos(x)|)+C

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integral of (1+tan(x))/2

\int \frac{1 + tan ( x )}{2} d x

\frac{1}{2} (x - ln ∣ cos (x) ∣) + C

Solution steps

\int \frac{1 + tan ( x )}{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int 1 + tan (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{2} (\int 1 d x + \int tan (x) d x)

\int 1 d x = x

\int tan (x) d x = - ln ∣ cos (x) ∣

= \frac{1}{2} (x - ln ∣ cos (x) ∣)

Add a constant to the solution

= \frac{1}{2} (x - ln ∣ cos (x) ∣) + C

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What is the integral of (1+tan(x))/2 ?
The integral of (1+tan(x))/2 is 1/2 (x-ln|cos(x)|)+C