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Popular >

integral of 6(x-1)

Solution

\int 6 (x - 1) d x

Solution

6 (\frac{x ^{2}}{2} - x) + C

Solution steps

\int 6 (x - 1) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int x - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 6 (\int x d x - \int 1 d x)

\int x d x = \frac{x ^{2}}{2}

\int 1 d x = x

= 6 (\frac{x ^{2}}{2} - x)

Add a constant to the solution

= 6 (\frac{x ^{2}}{2} - x) + C

Popular Examples

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\int - 2 e^{\frac{t}{4}} d t

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\int 6 x e^{- 3 x^{2}} d x

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\int sin (2 \frac{x}{2}) d x

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\int \frac{2}{x ^{5}} d x

integral of 6/(7x)+5e^{3x}+sqrt(x)

\int \frac{6}{7 x} + 5 e^{3 x} + x d x

Frequently Asked Questions (FAQ)

What is the integral of 6(x-1) ?
The integral of 6(x-1) is 6((x^2)/2-x)+C