What is the integral of (x^2+3x)/(sqrt(x)) ?

The integral of (x^2+3x)/(sqrt(x)) is 2/5 x^{5/2}+2x^{3/2}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (x^2+3x)/(sqrt(x))

\int \frac{x ^{2} + 3 x}{x} d x

\frac{2}{5} x^{\frac{5}{2}} + 2 x^{\frac{3}{2}} + C

Solution steps

\int \frac{x ^{2} + 3 x}{x} d x

Expand

\frac{x ^{2} + 3 x}{x} : \frac{x ^{2}}{x} + \frac{3 x}{x}

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{x ^{2}}{x} d x + \int \frac{3 x}{x} d x

\int \frac{x ^{2}}{x} d x = \frac{2}{5} x^{\frac{5}{2}}

\int \frac{3 x}{x} d x = 2 x^{\frac{3}{2}}

= \frac{2}{5} x^{\frac{5}{2}} + 2 x^{\frac{3}{2}}

Add a constant to the solution

= \frac{2}{5} x^{\frac{5}{2}} + 2 x^{\frac{3}{2}} + C

\int (6 x^{5}) d x

\int x^{2} (x^{3}) d x

\int \frac{2 ( csc ( t ) ) ^{2}}{cot ( t )} d t

\int (x^{3} + 1)^{- 1} d x

What is the integral of (x^2+3x)/(sqrt(x)) ?
The integral of (x^2+3x)/(sqrt(x)) is 2/5 x^{5/2}+2x^{3/2}+C