What is the integral of (9+tan^2(x)) ?

The integral of (9+tan^2(x)) is 8x+tan(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (9+tan^2(x))

\int (9 + tan^{2} (x)) d x

8 x + tan (x) + C

Solution steps

\int 9 + tan^{2} (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 9 d x + \int tan^{2} (x) d x

\int 9 d x = 9 x

\int tan^{2} (x) d x = - x + tan (x)

= 9 x - x + tan (x)

Simplify

= 8 x + tan (x)

Add a constant to the solution

= 8 x + tan (x) + C

\int \frac{x}{( x ^{3} + 1 )} d x

\int arcsin (3 t) d t

\int \frac{- 2 x}{e ^{x}} d x

\int \frac{x}{( x ^{2} - 3 x + 2 )} d x

\int (1 + 3 x^{2}) d x

What is the integral of (9+tan^2(x)) ?
The integral of (9+tan^2(x)) is 8x+tan(x)+C