What is the integral of 1/(x^2\sqrt[3]{x)} ?

The integral of 1/(x^2\sqrt[3]{x)} is -3/(4x^{4/3)}+C

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integral of 1/(x^2\sqrt[3]{x)}

- \frac{3}{4 x ^{\frac{4}{3}}} + C

Solution steps

Simplify

= \int \frac{1}{x ^{\frac{7}{3}}} d x

Apply the Power Rule

: - \frac{3}{4 x ^{\frac{4}{3}}}

= - \frac{3}{4 x ^{\frac{4}{3}}}

Add a constant to the solution

= - \frac{3}{4 x ^{\frac{4}{3}}} + C

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What is the integral of 1/(x^2\sqrt[3]{x)} ?
The integral of 1/(x^2\sqrt[3]{x)} is -3/(4x^{4/3)}+C