What is the integral of e^{-66x}x ?

The integral of e^{-66x}x is 1/4356 (-66e^{-66x}x-e^{-66x})+C

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integral of e^{-66x}x

\int e^{- 66 x} x d x

\frac{1}{4356} (- 66 e^{- 66 x} x - e^{- 66 x}) + C

Solution steps

\int e^{- 66 x} x d x

Apply u-substitution

: \int \frac{e ^{u} u}{4356} d u

= \int \frac{e ^{u} u}{4356} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4356} \cdot \int e^{u} u d u

Apply Integration By Parts

: e^{u} u - \int e^{u} d u

= \frac{1}{4356} (e^{u} u - \int e^{u} d u)

\int e^{u} d u = e^{u}

= \frac{1}{4356} (e^{u} u - e^{u})

Substitute back

u = - 66 x

= \frac{1}{4356} (e^{- 66 x} (- 66 x) - e^{- 66 x})

Simplify

= \frac{1}{4356} (- 66 e^{- 66 x} x - e^{- 66 x})

Add a constant to the solution

= \frac{1}{4356} (- 66 e^{- 66 x} x - e^{- 66 x}) + C

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What is the integral of e^{-66x}x ?
The integral of e^{-66x}x is 1/4356 (-66e^{-66x}x-e^{-66x})+C