en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of-0.08x+40

Solution

\int - 0.08 x + 40 d x

Solution

- 0.04 x^{2} + 40 x + C

Solution steps

\int - 0.08 x + 40 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 0.08 x d x + \int 40 d x

\int 0.08 x d x = 0.04 x^{2}

\int 40 d x = 40 x

= - 0.04 x^{2} + 40 x

Add a constant to the solution

= - 0.04 x^{2} + 40 x + C

Popular Examples

integral of xsqrt(R^2-x^2)

\int x R^{2} - x^{2} d x

integral of x(12x+6)

\int x (12 x + 6) d x

integral of 2x^2-4x+5

\int 2 x^{2} - 4 x + 5 d x

integral of ((2ln(x))/x)

\int (\frac{2 ln ( x )}{x}) d x

integral of (x^2+\sqrt[3]{x})^2

Frequently Asked Questions (FAQ)

What is the integral of-0.08x+40 ?
The integral of-0.08x+40 is -0.04x^2+40x+C