What is the integral of e^{1/10 t} ?

The integral of e^{1/10 t} is 10e^{1/10 t}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of e^{1/10 t}

\int e^{\frac{1}{10} t} d t

10 e^{\frac{1}{10} t} + C

Solution steps

\int e^{\frac{1}{10} t} d t

Apply u-substitution

: \int e^{u} \cdot 10 d u

= \int e^{u} \cdot 10 d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10 \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= 10 e^{u}

Substitute back

u = \frac{1}{10} t

= 10 e^{\frac{1}{10} t}

Add a constant to the solution

= 10 e^{\frac{1}{10} t} + C

\int (\frac{x + 16}{x ^{2} + 2 x - 8}) d x

\int 3 e^{0.6 x} d x

\int - \frac{e ^{- 2 x}}{2} d x

\int \frac{x}{x ^{3} - 1} d x

\int \frac{tan ^{2} ( x )}{cos ( x )} d x

What is the integral of e^{1/10 t} ?
The integral of e^{1/10 t} is 10e^{1/10 t}+C