What is the integral of (sin(e^{-x}))/(-2e^{3x)} ?

The integral of (sin(e^{-x}))/(-2e^{3x)} is -1/2 e^{-2x}cos(e^{-x})+e^{-x}sin(e^{-x})+cos(e^{-x})+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (sin(e^{-x}))/(-2e^{3x)}

\int \frac{sin ( e ^{- x} )}{- 2 e ^{3 x}} d x

- \frac{1}{2} e^{- 2 x} cos (e^{- x}) + e^{- x} sin (e^{- x}) + cos (e^{- x}) + C

Solution steps

\int \frac{sin ( e ^{- x} )}{- 2 e ^{3 x}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{- 2} \cdot \int \frac{sin ( e ^{- x} )}{e ^{3 x}} d x

Simplify

= (- \frac{1}{2}) \cdot \int \frac{sin ( e ^{- x} )}{e ^{3 x}} d x

Apply exponent rule:

\frac{1}{a ^{b}} = a^{- b}

\frac{sin ( e ^{- x} )}{e ^{3 x}} = (sin (e^{- x})) e^{- 3 x}

= (- \frac{1}{2}) \cdot \int sin (e^{- x}) e^{- 3 x} d x

Apply u-substitution

: \int - u^{2} sin (u) d u

= (- \frac{1}{2}) \cdot \int - u^{2} sin (u) d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= (- \frac{1}{2}) (- \int u^{2} sin (u) d u)

Apply Integration By Parts

: - u^{2} cos (u) - \int - 2 u cos (u) d u

= (- \frac{1}{2}) (- (- u^{2} cos (u) - \int - 2 u cos (u) d u))

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= (- \frac{1}{2}) (- (- u^{2} cos (u) - (- 2 \cdot \int u cos (u) d u)))

Apply Integration By Parts

: u sin (u) - \int sin (u) d u

= (- \frac{1}{2}) (- (- u^{2} cos (u) - (- 2 (u sin (u) - \int sin (u) d u))))

Use the common integral:

\int sin (u) d u = - cos (u)

= (- \frac{1}{2}) (- (- u^{2} cos (u) - (- 2 (u sin (u) - (- cos (u))))))

Substitute back

u = e^{- x}

= (- \frac{1}{2}) (- (- (e^{- x})^{2} cos (e^{- x}) - (- 2 (e^{- x} sin (e^{- x}) - (- cos (e^{- x}))))))

Simplify

(- \frac{1}{2}) (- (- (e^{- x})^{2} cos (e^{- x}) - (- 2 (e^{- x} sin (e^{- x}) - (- cos (e^{- x})))))) : - \frac{1}{2} e^{- 2 x} cos (e^{- x}) + e^{- x} sin (e^{- x}) + cos (e^{- x})

= - \frac{1}{2} e^{- 2 x} cos (e^{- x}) + e^{- x} sin (e^{- x}) + cos (e^{- x})

Add a constant to the solution

= - \frac{1}{2} e^{- 2 x} cos (e^{- x}) + e^{- x} sin (e^{- x}) + cos (e^{- x}) + C

\int \frac{e ^{6 x}}{x} d x

\int e^{6 s} d s

\int (x sec (x^{3}))^{2} d x

\int (\frac{x}{3} - 1)^{9} d x

\int (9 x^{2} + \frac{1}{x ^{3}}) d x

What is the integral of (sin(e^{-x}))/(-2e^{3x)} ?
The integral of (sin(e^{-x}))/(-2e^{3x)} is -1/2 e^{-2x}cos(e^{-x})+e^{-x}sin(e^{-x})+cos(e^{-x})+C