What is the integral of (1+tan^2(x))/(sec^2(x))-1 ?

The integral of (1+tan^2(x))/(sec^2(x))-1 is C

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integral of (1+tan^2(x))/(sec^2(x))-1

\int \frac{1 + tan ^{2} ( x )}{sec ^{2} ( x )} - 1 d x

C

Solution steps

\int \frac{1 + tan ^{2} ( x )}{sec ^{2} ( x )} - 1 d x

Rewrite using trig identities

= \int 0 d x

Integral of a constant:

\int a d x = a x

= 0 \cdot x

Simplify

= 0

Add a constant to the solution

= 0 + C

= C

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What is the integral of (1+tan^2(x))/(sec^2(x))-1 ?
The integral of (1+tan^2(x))/(sec^2(x))-1 is C