What is the integral of 1/(x^{2-4)} ?

The integral of 1/(x^{2-4)} is (x^3)/3+C

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integral of 1/(x^{2-4)}

\int \frac{1}{x ^{2 - 4}} d x

\frac{x ^{3}}{3} + C

Solution steps

\int \frac{1}{x ^{2 - 4}} d x

Apply the Power Rule

: \frac{x ^{3}}{3}

= \frac{x ^{3}}{3}

Add a constant to the solution

= \frac{x ^{3}}{3} + C

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