What is the integral of \sqrt[3]{x}+1 ?

The integral of \sqrt[3]{x}+1 is 3/4 x^{4/3}+x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of \sqrt[3]{x}+1

\frac{3}{4} x^{\frac{4}{3}} + x + C

Solution steps

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

\int 1 d x = x

= \frac{3}{4} x^{\frac{4}{3}} + x

Add a constant to the solution

= \frac{3}{4} x^{\frac{4}{3}} + x + C

\int \frac{1}{7 - 9 x} d x

\int \frac{x}{x ^{2} + x + 4} d x

\int (\frac{7}{x} - \frac{5}{x ^{6}}) d x

\int \frac{x ^{3} - x}{x ^{2}} d x

\int 20 + 0.2 q d q

What is the integral of \sqrt[3]{x}+1 ?
The integral of \sqrt[3]{x}+1 is 3/4 x^{4/3}+x+C