What is the integral of (2x-3)/(x^2-3x) ?

The integral of (2x-3)/(x^2-3x) is ln|x^2-3x|+C

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integral of (2x-3)/(x^2-3x)

\int \frac{2 x - 3}{x ^{2} - 3 x} d x

ln x^{2} - 3 x + C

Solution steps

\int \frac{2 x - 3}{x ^{2} - 3 x} d x

Apply u-substitution

: \int \frac{1}{u} d u

= \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= ln ∣ u ∣

Substitute back

u = x^{2} - 3 x

= ln x^{2} - 3 x

Add a constant to the solution

= ln x^{2} - 3 x + C

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What is the integral of (2x-3)/(x^2-3x) ?
The integral of (2x-3)/(x^2-3x) is ln|x^2-3x|+C