What is the integral of cos^9(3x)sin(3x) ?

The integral of cos^9(3x)sin(3x) is -1/30 cos^{10}(3x)+C

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integral of cos^9(3x)sin(3x)

\int cos^{9} (3 x) sin (3 x) d x

- \frac{1}{30} cos^{10} (3 x) + C

Solution steps

\int cos^{9} (3 x) sin (3 x) d x

Apply u-substitution

: \int cos^{9} (u) sin (u) \frac{1}{3} d u

= \int cos^{9} (u) sin (u) \frac{1}{3} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int cos^{9} (u) sin (u) d u

Apply u-substitution

: \int - v^{9} d v

= \frac{1}{3} \cdot \int - v^{9} d v

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} (- \int v^{9} d v)

Apply the Power Rule

: \frac{v ^{10}}{10}

= \frac{1}{3} (- \frac{v ^{10}}{10})

Substitute back

= \frac{1}{3} (- \frac{cos ^{10} ( 3 x )}{10})

Simplify

\frac{1}{3} (- \frac{cos ^{10} ( 3 x )}{10}) : - \frac{1}{30} cos^{10} (3 x)

= - \frac{1}{30} cos^{10} (3 x)

Add a constant to the solution

= - \frac{1}{30} cos^{10} (3 x) + C

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What is the integral of cos^9(3x)sin(3x) ?
The integral of cos^9(3x)sin(3x) is -1/30 cos^{10}(3x)+C