What is the integral of ((e^x-3x^2))/5 ?

The integral of ((e^x-3x^2))/5 is 1/5 (e^x-x^3)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of ((e^x-3x^2))/5

\int \frac{( e ^{x} - 3 x ^{2} )}{5} d x

\frac{1}{5} (e^{x} - x^{3}) + C

Solution steps

\int \frac{e ^{x} - 3 x ^{2}}{5} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{5} \cdot \int e^{x} - 3 x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{5} (\int e^{x} d x - \int 3 x^{2} d x)

\int e^{x} d x = e^{x}

\int 3 x^{2} d x = x^{3}

= \frac{1}{5} (e^{x} - x^{3})

Add a constant to the solution

= \frac{1}{5} (e^{x} - x^{3}) + C

\int x^{24} d x

\int (1 - sin^{2} (x)) (cos (x)) d x

\int (x^{2} - 4)^{2} (2 x^{2}) d x

\int \frac{2 x - 3}{x ^{2} + 9} d x

\int (2 x^{2} + 6)^{2} d x

What is the integral of ((e^x-3x^2))/5 ?
The integral of ((e^x-3x^2))/5 is 1/5 (e^x-x^3)+C