What is the integral of y(a+by^2) ?

The integral of y(a+by^2) is 1/2 y^2(a+by^2)-(by^4)/4+C

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integral of y(a+by^2)

\int y (a + b y^{2}) d y

\frac{1}{2} y^{2} (a + b y^{2}) - \frac{b y ^{4}}{4} + C

Solution steps

\int y (a + b y^{2}) d y

Apply Integration By Parts

: \frac{1}{2} y^{2} (a + b y^{2}) - \int b y^{3} d y

= \frac{1}{2} y^{2} (a + b y^{2}) - \int b y^{3} d y

\int b y^{3} d y = \frac{b y ^{4}}{4}

= \frac{1}{2} y^{2} (a + b y^{2}) - \frac{b y ^{4}}{4}

Add a constant to the solution

= \frac{1}{2} y^{2} (a + b y^{2}) - \frac{b y ^{4}}{4} + C

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What is the integral of y(a+by^2) ?
The integral of y(a+by^2) is 1/2 y^2(a+by^2)-(by^4)/4+C