What is the integral of sqrt(t^3-t^2) ?

The integral of sqrt(t^3-t^2) is 2/5 (t-1)^{5/2}+2/3 (t-1)^{3/2}+C

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integral of sqrt(t^3-t^2)

\int t^{3} - t^{2} d t

\frac{2}{5} (t - 1)^{\frac{5}{2}} + \frac{2}{3} (t - 1)^{\frac{3}{2}} + C

Solution steps

\int t^{3} - t^{2} d t

Simplify

t^{3} - t^{2} : t t - 1

= \int t t - 1 d t

Apply u-substitution

: \int (u + 1) u d u

= \int (u + 1) u d u

Expand

(u + 1) u : u^{\frac{3}{2}} + u

= \int u^{\frac{3}{2}} + u d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int u^{\frac{3}{2}} d u + \int u d u

\int u^{\frac{3}{2}} d u = \frac{2}{5} u^{\frac{5}{2}}

\int u d u = \frac{2}{3} u^{\frac{3}{2}}

= \frac{2}{5} u^{\frac{5}{2}} + \frac{2}{3} u^{\frac{3}{2}}

Substitute back

u = t - 1

= \frac{2}{5} (t - 1)^{\frac{5}{2}} + \frac{2}{3} (t - 1)^{\frac{3}{2}}

Add a constant to the solution

= \frac{2}{5} (t - 1)^{\frac{5}{2}} + \frac{2}{3} (t - 1)^{\frac{3}{2}} + C

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What is the integral of sqrt(t^3-t^2) ?
The integral of sqrt(t^3-t^2) is 2/5 (t-1)^{5/2}+2/3 (t-1)^{3/2}+C