Solution
Solution
Solution steps
Complete the square
Apply u-substitution
Apply Integral Substitution
Take the constant out:
Use the common integral:
Substitute back
Add a constant to the solution
Popular Examples
Frequently Asked Questions (FAQ)
What is the integral of 1/(x^2-16x+68) ?
The integral of 1/(x^2-16x+68) is 1/2 arctan((x-8)/2)+C