What is the integral of 1/(2sqrt(y^3)) ?

The integral of 1/(2sqrt(y^3)) is -1/(sqrt(y))+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 1/(2sqrt(y^3))

\int \frac{1}{2 y ^{3}} d y

- \frac{1}{y} + C

Solution steps

\int \frac{1}{2 y ^{3}} d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{1}{y ^{3}} d y

Apply exponent rule:

(a^{n})^{m} = a^{n \cdot m}

y^{3} = y^{\frac{3}{2}}

= \frac{1}{2} \cdot \int \frac{1}{y ^{\frac{3}{2}}} d y

Apply the Power Rule

: - \frac{2}{y}

= \frac{1}{2} (- \frac{2}{y})

Simplify

\frac{1}{2} (- \frac{2}{y}) : - \frac{1}{y}

= - \frac{1}{y}

Add a constant to the solution

= - \frac{1}{y} + C

\int x (e^{x} + 1) d x

\int - x y^{2} d x

\int \frac{12}{x ^{2} + 9} d x

\int \frac{( x ^{3} - 8 )}{x - 2} d x

\int ln (x^{2} - 81) d x

What is the integral of 1/(2sqrt(y^3)) ?
The integral of 1/(2sqrt(y^3)) is -1/(sqrt(y))+C