What is the integral of (20)/(sqrt(1-x^2)) ?

The integral of (20)/(sqrt(1-x^2)) is 20arcsin(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (20)/(sqrt(1-x^2))

\int \frac{20}{1 - x ^{2}} d x

20 arcsin (x) + C

Solution steps

\int \frac{20}{1 - x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 20 \cdot \int \frac{1}{1 - x ^{2}} d x

Use the common integral:

\int \frac{1}{1 - x ^{2}} d x = arcsin (x)

= 20 arcsin (x)

Add a constant to the solution

= 20 arcsin (x) + C

\int (1 1^{x}) d x

\int (t - \frac{1}{t})^{2} d t

\int (- e^{- x} sin (x) + e^{- x} cos (x)) d x

\int \frac{( x ^{2} - 1 )}{x ^{3} - 3 x + 1} d x

\int \frac{1}{x ^{2} - 6} d x

What is the integral of (20)/(sqrt(1-x^2)) ?
The integral of (20)/(sqrt(1-x^2)) is 20arcsin(x)+C