What is the integral of (4xy+3x^2) ?

The integral of (4xy+3x^2) is x^3+2yx^2+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (4xy+3x^2)

\int (4 x y + 3 x^{2}) d x

x^{3} + 2 y x^{2} + C

Solution steps

\int 4 x y + 3 x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 x^{2} d x + \int 4 y x d x

\int 3 x^{2} d x = x^{3}

\int 4 y x d x = 2 y x^{2}

= x^{3} + 2 y x^{2}

Add a constant to the solution

= x^{3} + 2 y x^{2} + C

\frac{sin ( x )}{1 + cos ^{2} ( x )}

\int (\frac{x ^{2}}{3}) d x

\int x^{19} sin (5 + x^{\frac{21}{2}}) d x

\int 13 x sec^{2} (x) d x

\int \frac{- x ^{2} + 3 x + 20}{3 x ^{3} + 12 x} d x