What is the integral of-sin(x)cos^6(x) ?

The integral of-sin(x)cos^6(x) is 1/7 cos^7(x)+C

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integral of-sin(x)cos^6(x)

\int - sin (x) cos^{6} (x) d x

\frac{1}{7} cos^{7} (x) + C

Solution steps

\int - sin (x) cos^{6} (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int sin (x) cos^{6} (x) d x

Apply u-substitution

: \int - u^{6} d u

= - \int - u^{6} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - (- \int u^{6} d u)

Apply the Power Rule

: \frac{u ^{7}}{7}

= - (- \frac{u ^{7}}{7})

Substitute back

u = cos (x)

= - (- \frac{cos ^{7} ( x )}{7})

Simplify

- (- \frac{cos ^{7} ( x )}{7}) : \frac{1}{7} cos^{7} (x)

= \frac{1}{7} cos^{7} (x)

Add a constant to the solution

= \frac{1}{7} cos^{7} (x) + C

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What is the integral of-sin(x)cos^6(x) ?
The integral of-sin(x)cos^6(x) is 1/7 cos^7(x)+C