What is the integral of 1/(x^{3/2)} ?

The integral of 1/(x^{3/2)} is -2/(x^{1/2)}+C

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integral of 1/(x^{3/2)}

integral

\frac{1}{x ^{\frac{3}{2}}}

- \frac{2}{x ^{\frac{1}{2}}} + C

Solution steps

\int \frac{1}{x ^{\frac{3}{2}}} d x

Apply the Power Rule

: - \frac{2}{x ^{\frac{1}{2}}}

= - \frac{2}{x ^{\frac{1}{2}}}

Add a constant to the solution

= - \frac{2}{x ^{\frac{1}{2}}} + C

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What is the integral of 1/(x^{3/2)} ?
The integral of 1/(x^{3/2)} is -2/(x^{1/2)}+C