What is the integral of 0.6sqrt(x) ?

The integral of 0.6sqrt(x) is 0.4x^{3/2}+C

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integral of 0.6sqrt(x)

\int 0.6 x d x

0.4 x^{\frac{3}{2}} + C

Solution steps

\int 0.6 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 0.6 \cdot \int x d x

Apply the Power Rule

: \frac{2}{3} x^{\frac{3}{2}}

= 0.6 \cdot \frac{2}{3} x^{\frac{3}{2}}

Simplify

0.6 \cdot \frac{2}{3} x^{\frac{3}{2}} : 0.4 x^{\frac{3}{2}}

= 0.4 x^{\frac{3}{2}}

Add a constant to the solution

= 0.4 x^{\frac{3}{2}} + C

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