What is the integral of (-4)/(x^3) ?

The integral of (-4)/(x^3) is 2/(x^2)+C

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integral of (-4)/(x^3)

\int \frac{- 4}{x ^{3}} d x

\frac{2}{x ^{2}} + C

Solution steps

\int \frac{- 4}{x ^{3}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 4 \cdot \int \frac{1}{x ^{3}} d x

Apply the Power Rule

: - \frac{1}{2 x ^{2}}

= - 4 (- \frac{1}{2 x ^{2}})

Simplify

- 4 (- \frac{1}{2 x ^{2}}) : \frac{2}{x ^{2}}

= \frac{2}{x ^{2}}

Add a constant to the solution

= \frac{2}{x ^{2}} + C

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