What is the integral of 9sin(5x) ?

The integral of 9sin(5x) is -9/5 cos(5x)+C

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integral of 9sin(5x)

\int 9 sin (5 x) d x

- \frac{9}{5} cos (5 x) + C

Solution steps

\int 9 sin (5 x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \int sin (5 x) d x

Apply u-substitution

: \int sin (u) \frac{1}{5} d u

= 9 \cdot \int sin (u) \frac{1}{5} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \frac{1}{5} \cdot \int sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= 9 \cdot \frac{1}{5} (- cos (u))

Substitute back

u = 5 x

= 9 \cdot \frac{1}{5} (- cos (5 x))

Simplify

9 \cdot \frac{1}{5} (- cos (5 x)) : - \frac{9}{5} cos (5 x)

= - \frac{9}{5} cos (5 x)

Add a constant to the solution

= - \frac{9}{5} cos (5 x) + C

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