What is the integral of 24x^3+34x+3 ?

The integral of 24x^3+34x+3 is 6x^4+17x^2+3x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 24x^3+34x+3

\int 24 x^{3} + 34 x + 3 d x

6 x^{4} + 17 x^{2} + 3 x + C

Solution steps

\int 24 x^{3} + 34 x + 3 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 24 x^{3} d x + \int 34 x d x + \int 3 d x

\int 24 x^{3} d x = 6 x^{4}

\int 34 x d x = 17 x^{2}

\int 3 d x = 3 x

= 6 x^{4} + 17 x^{2} + 3 x

Add a constant to the solution

= 6 x^{4} + 17 x^{2} + 3 x + C

\int \frac{- 7 t ^{5}}{t ^{2} + 2} d t

\int \frac{x - 9}{x + 4} d x

\int \frac{ln ( x ^{40} )}{x} d x

\int \frac{7 ^{3} x ^{5}}{2} d x

\int e^{2 s i n (2 x)} (2 cos (2 x)) d x

What is the integral of 24x^3+34x+3 ?
The integral of 24x^3+34x+3 is 6x^4+17x^2+3x+C