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Popular >

integral of 1/(y+4)

Solution

\int \frac{1}{y + 4} d y

Solution

ln ∣ y + 4 ∣ + C

Solution steps

\int \frac{1}{y + 4} d y

Apply u-substitution

: \int \frac{1}{u} d u

= \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= ln ∣ u ∣

Substitute back

u = y + 4

= ln ∣ y + 4 ∣

Add a constant to the solution

= ln ∣ y + 4 ∣ + C

Graph

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Frequently Asked Questions (FAQ)

What is the integral of 1/(y+4) ?
The integral of 1/(y+4) is ln|y+4|+C