What is the integral of 6e^{x/(100)} ?

The integral of 6e^{x/(100)} is 600e^{x/(100)}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 6e^{x/(100)}

\int 6 e^{\frac{x}{100}} d x

600 e^{\frac{x}{100}} + C

Solution steps

\int 6 e^{\frac{x}{100}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int e^{\frac{x}{100}} d x

Apply u-substitution

: \int e^{u} \cdot 100 d u

= 6 \cdot \int e^{u} \cdot 100 d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot 100 \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= 6 \cdot 100 e^{u}

Substitute back

u = \frac{x}{100}

= 6 \cdot 100 e^{\frac{x}{100}}

Simplify

= 600 e^{\frac{x}{100}}

Add a constant to the solution

= 600 e^{\frac{x}{100}} + C

\int \frac{e}{e ^{x}} d x

\int (2 x + e^{y}) d x

\int cos (5 - 7 x) d x

\int sin (\frac{nπ x}{20}) d x

\int (sec^{2} (θ) tan^{3} (θ)) d θ

What is the integral of 6e^{x/(100)} ?
The integral of 6e^{x/(100)} is 600e^{x/(100)}+C