What is the integral of (5x^4-2x^5) ?

The integral of (5x^4-2x^5) is x^5-(x^6)/3+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (5x^4-2x^5)

\int (5 x^{4} - 2 x^{5}) d x

x^{5} - \frac{x ^{6}}{3} + C

Solution steps

\int 5 x^{4} - 2 x^{5} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 5 x^{4} d x - \int 2 x^{5} d x

\int 5 x^{4} d x = x^{5}

\int 2 x^{5} d x = \frac{x ^{6}}{3}

= x^{5} - \frac{x ^{6}}{3}

Add a constant to the solution

= x^{5} - \frac{x ^{6}}{3} + C

\int x^{9} ln (2 x^{5}) d x

\int (\frac{1}{( 5 x - 3 ) ( 3 - 4 x )}) d x

\int \frac{arctan ( 2 t )}{1 + 4 t ^{2}} d t

\int sin^{3} (\frac{2 x}{3}) d x

\int \frac{x + 2}{( x ^{2} + 4 x - 1 ) ^{2}} d x

What is the integral of (5x^4-2x^5) ?
The integral of (5x^4-2x^5) is x^5-(x^6)/3+C