What is the integral of-(1/(x^2)) ?

The integral of-(1/(x^2)) is 1/x+C

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integral of-(1/(x^2))

\int - (\frac{1}{x ^{2}}) d x

\frac{1}{x} + C

Solution steps

\int - \frac{1}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int \frac{1}{x ^{2}} d x

Apply the Power Rule

: - \frac{1}{x}

= - (- \frac{1}{x})

Simplify

= \frac{1}{x}

Add a constant to the solution

= \frac{1}{x} + C

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