What is the integral from 0 to pi of (1-sin^3(x)) ?

The integral from 0 to pi of (1-sin^3(x)) is pi-4/3

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integral from 0 to pi of (1-sin^3(x))

\int_{0}^{π} (1 - sin^{3} (x)) d x

π - \frac{4}{3}

Decimal

1.80825 \dots

Solution steps

\int_{0}^{π} 1 - sin^{3} (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{π} 1 d x - \int_{0}^{π} sin^{3} (x) d x

\int_{0}^{π} 1 d x = π

\int_{0}^{π} sin^{3} (x) d x = \frac{4}{3}

= π - \frac{4}{3}

\int_{0}^{3} x + 3 d x

\int_{2}^{3} x^{4} + 3 x^{2} + 4 d x

\int_{- 2}^{0} \frac{1}{( x + 1 ) ^{2}} d x

\int_{0}^{c o s (x)} x d x

\int_{0}^{1} x arcsin (x) d x

What is the integral from 0 to pi of (1-sin^3(x)) ?
The integral from 0 to pi of (1-sin^3(x)) is pi-4/3