What is the integral from-1 to 1 of (sin(x))/(1+x^2) ?

The integral from-1 to 1 of (sin(x))/(1+x^2) is 0

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integral from-1 to 1 of (sin(x))/(1+x^2)

\int_{- 1}^{1} \frac{sin ( x )}{1 + x ^{2}} d x

0

Solution steps

\int_{- 1}^{1} \frac{sin ( x )}{1 + x ^{2}} d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

\frac{sin ( x )}{1 + x ^{2}} :

Odd

= 0

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\int_{0}^{t} t d t

What is the integral from-1 to 1 of (sin(x))/(1+x^2) ?
The integral from-1 to 1 of (sin(x))/(1+x^2) is 0