What is the derivative of In(x^3+x) ?

The derivative of In(x^3+x) is In(3x^2+1)

What is the first derivative of In(x^3+x) ?

The first derivative of In(x^3+x) is In(3x^2+1)

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\frac{d}{d x} (I n (x^{3} + x))

I n (3 x^{2} + 1)

Solution steps

\frac{d}{d x} (I n (x^{3} + x))

Treat

n, I

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= I n \frac{d}{d x} (x^{3} + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= I n (\frac{d}{d x} (x^{3}) + \frac{d x}{d x})

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d x}{d x} = 1

= I n (3 x^{2} + 1)

f (x) = 2 x^{2} + 7 x

x^{4} + 7 e^{x}

y = e^{3 x}, at x = \frac{1}{3} ln (5)

\frac{\partial}{\partial x} (\frac{5 x}{2 y})

\int_{0}^{1} (e^{- 0.2 t}) d t

What is the derivative of In(x^3+x) ?
The derivative of In(x^3+x) is In(3x^2+1)
What is the first derivative of In(x^3+x) ?
The first derivative of In(x^3+x) is In(3x^2+1)