What is the integral from 1 to 2 of 1/(xln(x)) ?

The integral from 1 to 2 of 1/(xln(x)) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 2 of 1/(xln(x))

\int_{1}^{2} \frac{1}{x ln ( x )} d x

diverges

Solution steps

\int_{1}^{2} \frac{1}{x ln ( x )} d x

Apply u-substitution

: \int_{0}^{l n (2)} \frac{1}{u} d u

= \int_{0}^{l n (2)} \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= [ln ∣ u ∣]_{0}^{l n (2)}

Compute the boundaries:

diverges

= diverges

\int_{2}^{0} e^{x^{2} - x} d x

\int_{0}^{1} (2 x + 1)^{2} d x

\int_{0}^{1} t e^{- \frac{t ^{2}}{2}} d t

\int_{0}^{π} sin^{2} (θ) d θ

\int_{0}^{2} 8 x e^{x^{2}} d x

What is the integral from 1 to 2 of 1/(xln(x)) ?
The integral from 1 to 2 of 1/(xln(x)) is diverges